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zlopas [31]
3 years ago
13

According to records from the last 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the

probability that it will be above 80' F for 20 or more days this June. There are 30 days in June.
Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

The answer is 0.59

Step-by-step explanation:

We can find the probability the event by thinking the event as binomial distribution. Probability of a day temperature higher than 80F is p=0.67 and the probability of a day temperature equal or lower that 80F is q=0.33. Therefore, the probability of more that 20 days are hotter than 80F in the June will be:

P(X\geq 20)=combination(30,20)*0.67^{20}*0.33^{10}+combination(30,21)*0.67^{21}*0.33^{9}+....+combination(30,30)*0.67^{30}*0.33^{0}=0.59

umka21 [38]3 years ago
6 0
I think the answer is 52% because I got it correct on i-Ready. I really hope this helps because I hate that when you fail you have to redo a lesson. 

Have a great day and let me know if this is the right answer. 
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Paula made this model to show the sum of two mixed numbers. Write the addition equation shown by the model and solve it.
kipiarov [429]

Answer:

3\frac{2}{3} + 2\frac{2}{3} = 6\frac{1}{3}

Step-by-step explanation:

Given

See attachment for number line

Required

Determine the model

From the attachment, we can see that each partition is 1/3

The gray rectangle covers 11 partitions.

So:

Gray = 11 * \frac{1}{3}

Gray = \frac{11}{3}

Express as a mixed number

Gray = 3\frac{2}{3}

The black rectangle covers 8 partitions

So:

Black= 8 * \frac{1}{3}

Black= \frac{8}{3}

Express as a mixed number

Black= 2\frac{2}{3}

So, the model is:

Gray + Black = Total

Where Total is the point where the black rectangle stops

3\frac{2}{3} + 2\frac{2}{3} = 6\frac{1}{3}

5 0
2 years ago
Explain how to get the product of 2 times the square root of 5 and 4 times the square root of 10
Vlad1618 [11]
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2 years ago
To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the
Lisa [10]

Solution :

Group   Before     After

Mean    693.75    743.75

Sd         155.37     143.92

SEM        54.93     50.88

n              8            8

Null hypothesis : The preparation course not effective.

$H_0: \mu_d = 0$

Alternative hypothesis : The preparation course is effective in improving the exam scores.

$H_a : \mu_d>0$  (after -  before)

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Answer:

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3 years ago
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