Can you take a picture of the question so I can solve it
126-27 = 99, hope this helps
Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
Answer:
8r+8pg-pq
Step-by-step explanation:
The subtractable pg cancels out one of the 9 pg's. So 9 pg-1 pg= 8 pg
Hope this helps!
Answer:
42.1 cm
Step-by-step explanation:
θ = 265°
Radius (r) = 9.1 cm
Arc length of major arc GH = θ/360 × 2πr
Plug in the values into the equation
Length of arc GH = 265/360 × 2 × π × 9.1
= 42.0886149
= 42.1 cm (nearest tenth)