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EastWind [94]
3 years ago
5

An auto transport truck holds 12 cars. A car dealer plans to bring in 1,150 new cars in June and July. If an auto transport truc

k is filled for each delivery, except for the last one, how many full truckloads are needed and how many cars will be in the last truck? 95 full truckloads with 12 cars on the 96th truck 96 full truckloads with 10 cars on the 97th truck 960 full truckloads with 10 cars on the 961st truck 95 full truckloads with 10 cars on the 96th truck
Mathematics
1 answer:
Vikki [24]3 years ago
4 0
12 x 95 = 1,140cars so 10 more cars would be on the 96th truck

Answer: 95 full truckloads with 10 cars on the 96th truck
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Answer:

(3x-4)(x-5)

Step-by-step explanation:

This is in the form

ax²+bx+c.

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60 = 1(60) or -1(-60); 2(30) or -2(-30); 3(20) or -3(-20); 4(15) or -4(-15); 5(12) or -5(-12); 6(10) or -6(-10).  The only of these that sum to -19 are -4 and -15.  This means we will split up -19x into -4x and -15x:

3x²-4x-15x+20

Next we group the first two terms and the last two terms:

(3x²-4x)+(-15x+20)

Factor out the GCF of each group.  For the first group, this is x:

x(3x-4)

For the second group, this is -5:

-5(3x-4)

The common factor for these two groups is (3x-4):

(3x-4)(x-5)

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3 years ago
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114 = 3x + 18
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114 = 3x + 18                                       114 = 3(y + 18)

-18            - 18                                      /3    /3

        =                                                     =

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    =                                                            =

32 = x                                                   20 = y

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