Question

Simplify the sum. (8u3 + 8u2 + 6) + (4u3 – 6u + 3)

Answer 1

-Hai There! :3


-Your answer and work for the question above should look like this: 


8u3+8u2+6+4u3−6u+3
=8u3+8u2+6+4u3+−6u+3
=8u3+8u2+6+4u3+−6u+3
=(8u3+4u3)+(8u2)+(−6u)+(6+3)
=12u3+8u2+−6u+9


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Answer 2

Answer:

$12u^{3}+8u^{2}-6u+9$

Step-by-step explanation:

we have

$(8u^{3}+8u^{2} +6)+(4u^{3}-6u+3)$

Group terms that contain the same variable

$(8u^{3}+4u^{3})+8u^{2}-6u+(6+3)$

Combine like terms

$(12u^{3})+8u^{2}-6u+(9)$

$12u^{3}+8u^{2}-6u+9$