Answer:
Three points that are member of the solution set could be (-2,10), (5,5) and (10,13)
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
The solution of the inequality A is the shaded area above the dashed line
-----> inequality B
The solution of the inequality B is the shaded area above the solid line
The solution of the system of inequalities is the shaded area between the dashed line and the solid line
see the attached figure
A solution to the system of inequalities is any point in the shaded area.
therefore
Three points that are member of the solution set could be (-2,10), (5,5) and (10,13)
-8.25x I believe
Explanation: when you add the two you get 8.25 but there are more negatives then positives so it’s gonna be negative and then you just add the x at the end
Just little pieces. Normally round chips or squares but you can use anything
2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
2 - 2sin^2 x + 3sin x = 0
2sin^2 x - 3sin x - 2 = 0
Let sin x = m, then
2m^2 - 3m - 2 = 0
2m^2 + m - 4m - 2 = 0
m(2m + 1) - 2(2m + 1) = 0
(m - 2)(2m + 1) = 0
m = 2 or m = -1/2
Now, sin x = -1/2
Therefore, x = 1/6(12nπ - π) and 1/6(12nπ + 7π)
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