Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.
C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC
Now, find another segment that also has a length of 6.
D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6
E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6
So, the segment congruent to AC is B. BE .
Answer:
Option C is the correct answer.
Step-by-step explanation:
Since a random number generator is used to select a single number between 1 and 28, inclusively;
For a fair decision to be made during the process, the number of persons in the set must be a divisor of 28.
Let's list the divisors of 28:
The divisors of 28 are {1, 2, 4, 7, 14, 28}
The only option that contains one of the divisors is option C which is 7.
Answer:
17c - 2
Step-by-step explanation:
Firstly, add the normal numbers together:
7c + 4 + 10c - 6
4 - 6 = -2
7c + 10c - 2
Now, the two numbers with a c value can be added together:
7c + 10c = 17c
This returns the answer:
17c - 2
Hope this helps!
Answer:
3.278 * 10 ^ 2
Step-by-step explanation:
To change a number to scientific notation you:
Move the decimal point to the left to make the number have 1 number before the decimal point.
From there you multiply by 10 to the power 2 the number of decimal points you moved.
So the answer is 3.278 * 10^2
HOPE IT HELPED
