A:
Table 1:
f(x) = 8x
X= cups so
ounces =
8* # of cups
Table 2:
f(x) =16x
X= pints so
ounces =
16*# of pints
Table 3:
f(x)= 32x
X= quarts so
ounces=
32*# of quarts
Note: another way instead of f(x)=kx is y=kx
B:
Depending on the slope we can easily find which is the steepest slope by easily comparing the slopes and seeing which is greater.
T1: 8
T2: 16
T3: 32
So, looking at our slopes, table 3 has the greatest slope because it has the greater slope out of the other two.
C:
The phrase, "rate of change" is another way to say the slope. To list again,
T1: 8
T2: 16
T3: 32
The table with the smallest slope would be table 1 since it is less than the other two tables.
I hope that helps, if you need any more assistance or you have any questions, please feel free to ask!!
Answer:
<u>B</u><u>.</u><u> </u>
Step-by-step explanation:
We answer that before thank you
What you need to do is find the greatest amount (1) and the lowest amount (1/4) of sap collected and the find how many times the lowest can go into the greatest. (So how many times can 1/4 go into 1). I believe that this is how you would do that.
Given a N quantity of numbers, the Geometric Mean is equal to the N-th root of product of the N numbers
In this case, we have two numbers, then we need to multiply them and take square root:
![\sqrt{40\cdot15}=\sqrt[]{600}=\sqrt[]{100\cdot6}=\sqrt[]{100}\cdot\sqrt[]{6}=10\sqrt[]{6}](https://tex.z-dn.net/?f=%5Csqrt%7B40%5Ccdot15%7D%3D%5Csqrt%5B%5D%7B600%7D%3D%5Csqrt%5B%5D%7B100%5Ccdot6%7D%3D%5Csqrt%5B%5D%7B100%7D%5Ccdot%5Csqrt%5B%5D%7B6%7D%3D10%5Csqrt%5B%5D%7B6%7D)
The answer is:
10√6
Rounded is Approximately 24.5
The answer for this problem is 2 since it is not specified whether it is adjacent to the right or adjacent to the left.
If it is adjacent to the right, the answer is:
p (k) = 2 * p(1) + 2 * k
If the is adjacent to the left, the answer is:
P (k) = 2 *p(1) +2 * (k-2)
