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Komok [63]
3 years ago
10

How do I solve n^2-5n-14=0 by factoring

Mathematics
2 answers:
Tju [1.3M]3 years ago
5 0
(N-7)(n+2)=0 as you'd get n^2-7n+2n-14 then just simplify. Then it would be n=-2 or 7
bogdanovich [222]3 years ago
5 0
n^2-5n-14=0 \\
n^2-7n+2n-14=0\\
n(n-7)+2(n-7)=0\\
(n+2)(n-7)=0\\
n=-2 \vee n=7
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