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gladu [14]
3 years ago
9

How to factor x^2-10x+25?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

To factor: Notice that when you factor it should turn out to be a binomial x binomial.

x^2-10x+25

When factoring you can look at the operation at the end right before the last digit.  If the operation is positive then you will use the first operation in the binomial for factored number.  For example the ending operation is positive and the first operation is subtraction so both binomial will be subtraction.

I know it would be factored (x-5)(x-5) and I can prove it by multiplying it out.

x^2 -5x-5x+25

x^2-10x+25

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X^2-5x=-4 . I need to find the zeroes
GrogVix [38]
The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:

X² - 5x + 4 = 0

Factor the equation:

(x - 1)(x - 4) = 0

Now calculate each piece separately, starting with the first one:

x - 1 = 0

Add 1 to both sides of the equation:

x = 1

We have proven that x = 1. Now calculate the second piece:

x - 4 = 0

Add 4 to both sides of the equation:

x = 4

We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.

I hope this helps!
4 0
4 years ago
PLS HELP BEST ANSWER=BRAINLIEST
8_murik_8 [283]

Answer:

a-2=a-2

Step-by-step explanation:

Here it is, you just have to notice that the numerator has common factors alternated. You will then collect the same parentheses and simplify with the denominator.

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2 years ago
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3 years ago
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