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3 years ago

Please help me please The graphs below have the same shape. Complete the equation of the blue

Mathematics

2 answers:

ad-work [718]3 years ago

5 0

Answer:

Step-by-step explanation:

8090 [49]3 years ago

3 0

Answer:

3 you add the g to the x and it makes 3 hope help ask me more if you need more quistions. please mark brainlest please

Step-by-step explanation:

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I need help PLEASE!!!

Hitman42 [59]

Answer:

1. ∠A and ∠B are right angles. Given

2. m∠A = m∠ B All right angles are congruent.

3. ∠BEC≅ ∠AED Vertical angles are congruent

4. ΔCBE ~ ΔDAE AA

Step-by-step explanation:

A proof always begins with the givens.

1. ∠A and ∠B are right angles. -------------->Given

2. m∠A = m∠ B are equal since-----------> All right angles are congruent.

3. ∠BEC≅ ∠AED are also equal since---->Vertical angles are congruent

4. ΔCBE ~ ΔDAE since two angles are equal----------> AA

7 0

3 years ago

Find f(-2). f(x) = 9x2 - 5x + 2 A) 14 B) 18 C) 28 D) 48

kifflom [539]

F(x) = 9x² - 5x + 2

f(-2) = 9(-2)² - 5(-2) + 2
f(-2) = 36 + 10 + 2
f(-2) = 48

3 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago

Some one help please algebra .. -6=3x-6y 4x=4+5x

yanalaym [24]

X=2y-2

x=-4

hope i helped

5 0

3 years ago

Read 2 more answers

Given that the value of x is between 0 and 360 degrees (0 and 360

Brums [2.3K]

Answer:

150° and 210°
0

Step-by-step explanation:

It is convenient to memorize the trig functions of the "special angles" of 30°, 45°, 60°, as well as the way the signs of trig functions change in the different quadrants. Realizing that the (x, y) coordinates on the unit circle correspond to (cos(θ), sin(θ)) can make it somewhat easier.

You have memorized that cos(x) = (√3)/2 is true for x = 30°. That is the reference angle for the 2nd-quadrant angle 180° -30° = 150°, and for the 3rd-quadrant angle 180° +30° = 210°.

Cos(x) is negative in the 2nd and 3rd quadrants, so the angles you're looking for are

150° and 210°

<h3>Bonus</h3>

You have memorized that sin(π/4) = √2/2, and that cos(3π/4) = -√2/2. The sum of these values is ...

√2/2 + (-√2/2) = 0

_____

Additional comments

Your calculator can help you with both of these problems.

The coordinates given on the attached unit circle chart are (cos(θ), sin(θ)).

6 0

2 years ago