<h3><u>Answer:</u></h3>

<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

Here,
- hypotenuse = 23 feet
= 76°- Value of Sin
= 0.97 - Perpendicular = ?





ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

<span>Since one standard deviation is 20 luggages, 3 standard deviations above the mean is 3*20=60 luggages above the mean of 380 luggages, so 60+380 gives the answer C, 440.</span>
Answer:
X= 1/2 Y= 5
Step-by-step explanation:
8x+7y=39-------------(1)--------×2
4x-14y= -68-----------(2)-------×1
16X + 14Y = 78--------(3)
4X- 14Y = -68----------(4)
Addy equation (4) and (3)
20X = 10
dividing bothsides by 20
20X/20= 10/20
X = 1/2
substitute the value of X into equation (1)
8X+7Y = 39
8(1/2)+7Y= 39
4+7Y = 39
7Y = 39-4
7Y = 35
dividing bothsides 7
7Y= 35/7
Y = 5
Answer:
The equation of the sraight line 3x- y+ 6 =0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the gradient of the function
|gradf| = 3 and point (-1,3)
Given that the slope of the line
m = 3
The equation of the straight line passing through the point(-1,3) and slope m =3

y-3 = 3(x-(-1))
y-3 = 3x+3
3x +3-y+3=0
3x- y+ 6 =0
<u><em>Final answer:-</em></u>
The equation of the sraight line 3x- y+ 6 =0
<u><em></em></u>