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Maslowich
3 years ago
8

I am confused on how to solve: Cot^2(t)/sin^2(t) = csc(t) - sin(t)

Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer: 90°

Step-by-step explanation:

scs(t)=1/sint

sint²+cost²=1

cot t=(cost/sint)²

(cost²/sint²)/Sint²=1/sint-sint

cost²/sint⁴=1/sint-sint

cost²=sint³-sint⁵

Cost²=sint³(1-sint²)

cost²=sint³cost²

1=sint³

sint=1

arcsin1=90°

Cot^2(t)=(cost/sint)²

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A trapezoid has a height of 6 inches, an area of 120 square inches, and one base measuring 13 inches. Find the length of the oth
kirill [66]

Answer:

27

Step-by-step explanation:

Givens

b1 = 13

b2 = ?

h = 6

Area = 120

Formula

Area = (b1 + b2) * h/2         Multiply by 2

2Area = (b1 + b2)*h           Divide by h

2Area/h = b1 + b2              Subtract b1 from both sides

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Solution

2*120 / 6 - 13 = b2

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