We have a triangle whose perimeter is 32 feet. Some information regarding the sides of the triangle is given:
GiveN:
- One side is 3 times the second side.
- Third side is 12 feet longer than the second side.
As we can see that, two sides of the triangle are defined the second sides. It means First and third side can be expressed in the form of second side.
- So let the second side be x
Then,
- First side = 3x
- And, third side = x + 12
We know that, perimeters is the sum of the lengths of all sides of the triangle, So it can be written as:

Solving it further,

Subtracting 12 from both sides,


Dividing 5 from both sides,


Then,
- First side = 3x = 12 feet
- Second side = 4 feet
- Third side = x + 12 = 16 feet
And we are done with the answer !!
#CarryOnLearning
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The question does not seem complete, but I'll represent the statement mathematically and look for their ages each. This is because the worst they can ask for is their ages.
Let C stand for Courtney's age, A for Andrei's age, N for Natalie's age and S for Shari's age. From the question we can deduce the following:
C = 2A
C = N + 3
C = S/2
S - N = C + A
S = 2C, N = C - 3 and A = C/2, therefore we have
2C - (C - 3) = C + C/2
C + 3 = C + C/2
C/2 = 3 and C = 6
A = C/2
A= 6/2
A = 3
N = C - 3
N = 6 - 3
N = 3
S = 2C
S = 2 x 6
S = 12.
C = 6, A = 3, N = 3 and S = 12
Answer:
y=x+8 and y=3x
Step-by-step explanation:
The Given point is (4,12)
now we can substitute the point in each of the function and check wether it lies on it or not.
A. y=x+8
substitute y=12,x=4
12=4+8=12 which is true
B. y=3x
substitute y=12,x=4
12=3*4=12 which is true
C. y=2x
substitute y=12,x=4
12=2*4=8 which is not true
D. y=x+6
substitute y=12,x=4
12=4+6=10 . which is not true
Therefore option A and B are correct.
#1 √ 75
Answer : 5√3 or ≈ 8.66025
#2 √ 48
Answer : 4√3 or ≈ 6.9282
#3 √ 128
Answer : 8√2 or ≈ 11.31371
#4 √ 300
Answer : 10√3 or ≈ 17.32051
~~
#5 √⅔
Answer :

#6 √16/4
Answer : 2
#7 √ 6/8
Answer :

#8 √27/9
Answer : √ 2 or ≈ 1.73205
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey