Question

The mean is μ = 15.2 and the standard deviation is σ = 0.9. find the probability that x is greater than 17.

Answer 1

The probability that x >17 will be found as follows:
the z-score is given by:
z=(17-15.2)/0.9=2
Thus
P(X>17)=1-P(x<17)=P-(z=2)
=1-0.9772
=0.0228

Answer 2

Answer:

0.0228

Step-by-step explanation:

Note: mean is the sum of observation divided by the number of observation. It is also the summation of elements in the sample space divided by the frequency of occurrence in the sample space

probability is the likelihood of an event to occur.

The mean is 15.2 and the standard deviation is 0.9. Find the probability that X is greater than 17.

-------

z(17) = (17-15.2)/0.9 = 2

P(x > 17) = P(z > 2) = normalcdf(2,100) = 0.0228

checking the normal distribution table we get 0.0228