Answer:
x^2 + (y - k)^2 = 131
Step-by-step explanation:
The general equation is (x - h)^2 + (y - k)^2 = r^2.
If the center is (h, k) and h = 0, then we have
2(x + 32)
Let "a number" = x
Note "the sum (addition) of a number and thirty-two" = x + 32
"Twice (of the above)" (multiplication) = 2(x + 32)
2(x + 32) is your answer.
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x^2 + 2x - 15
(x-3)(x+5) = x^2 + 2x - 15
hope this helps, pls mark brainliest :D
Given that:
