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OverLord2011 [107]

3 years ago

10

Last month Sarah Ryan and Taylor received a total of 882 emails if Sarah receive 25% more emails than the sum of the numbers of

emails received by Ryan and Taylor how many emails and Sarah receive

2 answers:

Mrac [35]3 years ago

6 0

The answer is GOING TO BEBEEEEEEEEEEEEEEEEEEEEEEEEEEEE 486.

Nesterboy [21]3 years ago

5 0

S+R+T=882

S=1.25(R+T)

S=1.25(882-S)

S=1102.5-1.25S

2.25S=1102.5

S=490

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3 years ago

What are the changes in education for self reliance

Y_Kistochka [10]

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4 years ago

check three statements that help jeffreson advance his argument for why the colonies should break free

Sonja [21]

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The King Has Refused To Pass Laws That Would Help The Colonists.

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3 0

3 years ago

Una tractomula se desplaza con rapidez de 69 km/h. Cuando el conductor ve una vaca atravesada en medio de la carretera, acciona

irinina [24]

Responder:

El remolque del tractor no atropellará a la vaca.

Explicación:

Dado lo siguiente:

Velocidad del tractor remolque: 69 km / h

Tiempo necesario para detenerse después de aplicar los frenos = 4 segundos

Distancia de vacas desde el remolque del tractor = 25 metros

Por lo tanto, la distancia recorrida por el remolque del tractor después de aplicar los frenos:

Velocidad del tractor remolque / Tiempo

69 km / h = (69 * 1000) m / 3600s = 69000m / 3600s = 19.17m / s

(19,17 m / s ÷ 4 s) = 4,8 m

Como la distancia de la vaca está más lejos (25 m), el remolque del tractor no pasará por encima de las vacas

3 0

3 years ago

What volume would be occupied by 4.8 g of oxygen gas at 0.50 atm and 133 °c? (o: 15.999)

castortr0y [4]

The volume occupied by this oxygen gas is equal to 10.0 Liters.

<u>Given the following data:</u>

Mass of oxygen gas = 4.8 grams

Pressure = 0.50 atm

Temperature = 133°C to Kelvin = $273 +133=406\;K$

Molar mass of oxygen gas = $2 \times 15.999$ = 31.998 g/mol.

<u>Scientific data:</u>

Ideal gas constant, R = 0.0821 L⋅atm/mol⋅K

To determine the volume occupied by this oxygen gas:

First of all, we would calculate the number of moles of oxygen gas;

$Number\;of\;moles = \frac{Mass}{molar\;mass}\\\\Number\;of\;moles = \frac{4.8}{31.998 }$

Number of moles = 0.15 moles.

Now, we can determine the volume by using the ideal gas law equation;

$V = \frac{nRT}{P}$

<u>Where;</u>

P is the pressure.

V is the volume.

n is the number of moles of a gas.

R is the ideal gas constant.

T is the temperature.

Substituting the given parameters into the formula, we have;

$V =\frac{0.15 \times 0.0821 \times 406}{0.50} \\\\V =\frac{4.99989}{0.50}$

Volume, V = 9.9998 ≈ 10.0 Liters.

Read more on volume here: brainly.com/question/25290815

7 0

3 years ago