Answer:
0.756
Step-by-step explanation:
It is given that a machine has four components, A, B, C, and D.
If these components set up in such a manner that all four parts must work for the machine to work properly.
We need to find the probability that the machine works properly. It means we have to find the value of 
.
If two events X and Y are independent, then
Assume the probability of one part working does not depend on the functionality of any of the other parts.
Substitute the given values.
Therefore, the probability that the machine works properly is 0.756.
Answer:
do you still need this answered?
Step-by-step explanation:
<h2>Answer</h2>
f(x) = 5(1.25)x + 4
<h2>Explanation</h2>
To solve this, we are going to use the standard exponential equation:
where
is the initial amount
is the growth rate in decimal form
is the time (in months for our case)
Since the hours of classic music remain constant, we just need to add them at the end. We know form our problem that Sue initially has 5 hours of pop, so 
; we also know that every month onward, the hours of pop music in her collection is 25% more than what she had the previous month, so 
. Now let's replace the values in our function:
Now we can add the hours of classical music to complete our function:
Note: The equations written in this questions are not appropriately expressed, however, i will work with hypothetical equations that will enable you to solve any problems of this kind.
Answer:
For the system of equations to be unique, s can take all values except 2 and -2
Step-by-step explanation:
![\left[\begin{array}{ccc}2s&4\\2&s\end{array}\right] \left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right] = \left[\begin{array}{ccc}-3 \\6 \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2s%264%5C%5C2%26s%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B1%7D%20%5C%5Cx_%7B2%7D%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%20%5C%5C6%20%5Cend%7Barray%7D%5Cright%5D)
For the system to have a unique solution, 
