V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.
Answer:
(x²/4) + (y²/16) ≤ 1
Step-by-step explanation:
The general form of the ellipse in the graph is
x²/4 + y²/16 = 1
we want to find the inequality which represents the shaded area this will determine whether which of the following 2 choices are correct
Choice 1: x²/4 + y²/16 ≥ 1
Choice 2: x²/4 + y²/16 ≤ 1
we note that point (0,0) lies inside the shaded area. Which means if we substitute (0,0), it should create an equality that is valid.
try choice 1: 0²/4 + 0²/16 = 0 ≥ 1 (not valid because obviously zero is smaller than 1)
try choice 1: 0²/4 + 0²/16 = 0 ≤ 1 (this is valid, hence choice 2 is the answer)
Answer:
A theorem is a general proposition not self-evident but proved by a chain of reasoning; a truth established by means of accepted truths.
Step-by-step explanation:
Answer: ![\bold{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cbold%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
<u>Step-by-step explanation:</u>
![\dfrac{1}{2}\sqrt[4]{32} =\dfrac{1}{2}\sqrt[4]{2\cdot 2\cdot 2\cdot 2\cdot 2}=\dfrac{1}{2}\cdot 2\sqrt[4]{2}=\boxed{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B32%7D%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B2%5Ccdot%202%5Ccdot%202%5Ccdot%202%5Ccdot%202%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%202%5Csqrt%5B4%5D%7B2%7D%3D%5Cboxed%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
Answer:
54
Step-by-step explanation:
