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3 years ago

Describe the difference between 33 1/3 and 33%

Mathematics

1 answer:

Neko [114]3 years ago

8 0

33 is a decimal
1/3 is a fraction
33% is a percentage

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It took Fred 17 days to save $36.55. At that rate, how long would it take him to save $70.95?

Vlad1618 [11]

Answer:

Fred would take 33 days to save $ 70.95.

Step-by-step explanation:

The number of days ( $t$ ) is directly proportional to the quantity of money saved ( $c$ ), in monetary units, then we can calculate the time taken to save $ 70.95 by simple rule of three:

$t = 17\,d\,\times \frac{\$\,70.95}{\$\,36.55}$

$t = 33\,d$

Fred would take 33 days to save $ 70.95.

4 0

3 years ago

What's the ratio of 75 to 80?

oksano4ka [1.4K]

Answer:

75:80 OR 15:16

Step-by-step explanation:

7 0

3 years ago

Find the area use 3.14 for pi

Aleonysh [2.5K]

Answer:

15.14 cm^2

Step-by-step explanation:

Area of rectangle = 4cm x 3 cm = 12cm^2

Radius of the circle = 2 cm

Area of 1/4 of a circle = (pi x r^2) / 4

= (3.14 x 4) / 4 = 3.14 cm^2

3.14 cm^2 + 12cm^2 = 15.14 cm^2

5 0

3 years ago

Find the product. (-3ab2)3 -27 a3b6 -9 a3b5 -23 a2b2 27 ab

7nadin3 [17]

Answer:

a) -27 a³ b⁶

Step-by-step explanation:

Explanation:-

Given ( -3 ab² )³

By using (ab )ⁿ = aⁿ bⁿ

( -3 ab² )³ = (-3)³ a³ (b²)³

Again , using formula $(a^{m} )^{n} = a^{mn}$

= -27 a³ b⁶

6 0

3 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

3 years ago

Read 2 more answers