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Luda [366]
3 years ago
6

Complete the paragraph to explain how Angelina can notify readers that her report is just a draft.

Computers and Technology
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

Background

Design

Page background

Custom

Explanation:

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You are developing a system to process lists of days of the week, represented as strings. Create a function is_weekend that cons
Dafna11 [192]

Answer:

   public static boolean is_weekend(List week){

       if(week.contains("Saturday")||week.contains("Sunday"))

       {

           System.out.println("List has a weekend");

           return true;

       }

       else{

           System.out.println("List has no weekend");

           return false;

       }

   }

Explanation:

  • Using java programming language
  • Import <em>java.util.ArrayList</em> and <em>import java.util.List;</em> so you can implement a java list
  • Create a list and add the days of the week
  • Create the required method using the contains() method to check for Sunday and Saturday and return true if the list contains them
  • See the complete program with a call to the method

<em>import java.util.ArrayList;</em>

<em>import java.util.List;</em>

<em>public class Car {</em>

<em>    public static void main(String[] args) {</em>

<em>        List<String> daysOfWeek = new ArrayList<>();</em>

<em>        daysOfWeek.add("Sunday");</em>

<em>        daysOfWeek.add("Moday");</em>

<em>        daysOfWeek.add("Tuesday");</em>

<em>        daysOfWeek.add("Wednesday");</em>

<em>        daysOfWeek.add("Thursday");</em>

<em>        daysOfWeek.add("Friday");</em>

<em>        daysOfWeek.add("Saturday");</em>

<em>        is_weekend(daysOfWeek);</em>

<em>    }</em>

<em>    public static boolean is_weekend(List week){</em>

<em>        if(week.contains("Saturday")||week.contains("Sunday"))</em>

<em>        {</em>

<em>            System.out.println("List has a weekend");</em>

<em>            return true;</em>

<em>        }</em>

<em>        else{</em>

<em>            System.out.println("List has no weekend");</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

}

5 0
3 years ago
Jamie plans to sell his pottery designs through his website. If he also wants to launch a mobile app to reach more people, which
Liula [17]
He should launch an M-commerce app
5 0
2 years ago
Question 5 (frue/False Worth 3 points)
azamat

<em><u>true</u></em>

Explanation:

<em><u>because</u></em><em><u> </u></em><em><u>logical</u></em><em><u> </u></em><em><u>errors</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>unexpected</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>before</u></em>

5 0
3 years ago
Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If user
Sedbober [7]

Answer:

Replace /* Your solution goes here */ with:

cin>>matchValue;

numMatches = 0;

for (i = 0; i < userValues.size(); ++i) {

if(matchValue == userValues.at(i))

{

numMatches++;

}

}

Explanation:

This line gets input for matchValue

<em>cin>>matchValue; </em>

This line initializes numMatches to 0

<em>numMatches = 0; </em>

The following iteration checks for the number of matches (numMatches) of the matchValue

<em>for (i = 0; i < userValues.size(); ++i) { </em>

<em>if(matchValue == userValues.at(i)) </em>

<em>{ </em>

<em> numMatches++; </em>

<em>} </em>

<em>} </em>

<em>See Attachment for full source code</em>

Download cpp
3 0
3 years ago
Taylor develops a prototype for a new smartphone. It only includes code, a way to process the input, a memory card, and a microp
marysya [2.9K]

Answer:

i would say C.output

Explanation:

the program would be the code, the input would be the input, and the memory card would be the memory leaving the output as the only thing forgotten.

6 0
3 years ago
Read 2 more answers
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