The default paper size is _____. a. letter b. legal c. executive d. statement

Write a single instruction that inverts bits 5 and 6 in the bl register

katrin [286]

The single instruction that can inverts bits 5 and 6 in the bl register is xor bl,1100000b.

<h3>What is single instruction?</h3>

Single Instruction is a term that connote all the data streams are said to be processed though the use of the same compute logic.

Note that in the case above, the single instruction that can inverts bits 5 and 6 in the bl register is xor bl,1100000b.

Learn more about bits from

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5 0

2 years ago

There are information that are in the web view source that may not appear on the web page such as meta name. In addition there c

SCORPION-xisa [38]

Answer:

True on a web page such meta name will not appear in web view source and irrelevant information will be displayed.

Explanation:

Basically web page source is compiled version of HTML script so the end-user he or she tries to view pages system will show only in HTML.

so meta name information and active object information will not be displayed while viewing the web source code instead of that the irrelevant informant ions will be displayed and end-user cannot under anything out of the web source code.

Moreover, even the client side validation script also will not be displayed.

Only HTML will be displayed

3 0

3 years ago

1. How has ESPN handled the rise of Twitter? How has it incorporated Twitter into Sports Center?

vovangra [49]

Rise of Twitter:

On every sport telecast ESPN create a twitter accountants raise a sport questions related to sport telecasted. Base of sport interested person answer queries or questions so automatically incorporated to sport center

Cable subscriptions:

Since ESPN been telecasted through air with customer login with minimum subscription fees so end user easily login n watch the match online and live telecast. Moreover end user can watch old or missed match from archive library on its own time.

ESPN is subscription channel are also available as bundle option in hot star amazon prime video.

ESPN upgrade:

ESPN telecast match on season basic such as football, cricket extra. ESPN very frequently upgrade the match schedule and old archives. Sports person interviews n performance of software also is upgraded to end users.

4 0

3 years ago

Read 2 more answers

g Suppose the vertex data is stored in an array named verts and each vertex uses a list to store the coordinates. Write the code

kodGreya [7K]

Answer:

function createAndFillBufferObject(gl, data) {

var buffer_id;

// Create a buffer object

buffer_id = gl.createBuffer();

if (!buffer_id) {

out.displayError('Failed to create the buffer object for ' + model_name);

return null;

}

// Make the buffer object the active buffer.

gl.bindBuffer(gl.ARRAY_BUFFER, buffer_id);

// Upload the data for this buffer object to the GPU.

gl.bufferData(gl.ARRAY_BUFFER, data, gl.STATIC_DRAW);

return buffer_id;

}

3 0

4 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

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3 0

2 years ago