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Alja [10]
2 years ago
10

f 20% of the population are homozygous for the scalp-wiggling allele •(qq, or q 2), then what proportion of the population is ho

mozygous for the non-wiggling allele?
Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
7 0

Answer:

The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

Step-by-step explanation:

Denote the variables as follows:

<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.

<em>p²</em> = number of people who are homozygous for the non-wiggling allele.

It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.

Compute the value of <em>q</em> as follows:

q^{2}=0.20\\q=\sqrt{0.20}\\=0.4472

Compute the value of <em>p</em> as follows:

p=1-q\\=1-0.4472\\=0.5528

Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:

p^{2}=(0.5528)^{2}=0.30558784\approx0.3056

Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

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