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Alja [10]
3 years ago
10

f 20% of the population are homozygous for the scalp-wiggling allele •(qq, or q 2), then what proportion of the population is ho

mozygous for the non-wiggling allele?
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

Step-by-step explanation:

Denote the variables as follows:

<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.

<em>p²</em> = number of people who are homozygous for the non-wiggling allele.

It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.

Compute the value of <em>q</em> as follows:

q^{2}=0.20\\q=\sqrt{0.20}\\=0.4472

Compute the value of <em>p</em> as follows:

p=1-q\\=1-0.4472\\=0.5528

Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:

p^{2}=(0.5528)^{2}=0.30558784\approx0.3056

Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

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Answer:

m ≠1  ( all m in R  except 1 )

Step-by-step explanation:

hello :

mx − y + 3 = 0.....(*)

(2m − 1)x − y + 4 = 0 ....(**)

multiply (*) by : -1       you have :   -mx+y-3=0   ....(***)

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Step-by-step explanation:

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A sample of 13 sheets of cardstock is randomly selected and the following thicknesses are measured in millimeters. Give a point
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<h3>Answer:  0.061</h3>

===============================================

Explanation:

Add up the values to get

1.96+1.81+1.97+1.83+1.87+1.84+1.85+1.94+1.96+1.81+1.86+1.95+1.89= 24.54

Then divide over 13 (the number of values) to get 24.54/13 = 1.8876923 which is approximate.

So the mean is approximately 1.8876923

---------------------

Now make a spreadsheet as shown below

We have the first column as the x values, which are the original numbers your teacher provided. The second column is of the form (x-M)^2, where M is the mean we computed earlier. We subtract off the mean and square the result.

After we compute that column of (x-M)^2 values, we add them up to get what is shown in the highlighted yellow cell at the bottom of the column.

That sum is approximately 0.04403076924

Next, we divide that over n-1 = 13-1 = 12

0.04403076924 /12 = 0.00366923077

That is the sample variance. Apply the square root to this to get the sample standard deviation. This is the point estimate of the population standard deviation. As the name implies, it works for samples that estimate population parameters.

sqrt(0.00366923077) = 0.06057417576822

This rounds to 0.061 which is the final answer.

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2 years ago
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