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2 years ago

Solve pls brainliest

Mathematics

1 answer:

Fofino [41]2 years ago

3 0

Answer:

Yes

Step-by-step explanation:

-42/6 = -7

17/18 = 0.9444444 (4 repeating)

Integers = whole numbers whether negative or not, but it does not have a decimal.

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Maria’s phone bills were $95, $67, $43, and $115. What was the mean, or average, of her phone bills?

jeka57 [31]

Add all her phone bills = 115+43+67+95 =320, divide by how many numbers there are, so 4, 320 divided by 4 = 80

4 0

2 years ago

Implicit differentiation in terms of x and y

Volgvan

For implicit differentiation, you are using the chain rule
$f'(x) = g'(u(x))* \frac{du}{dx}$
Except u(x) = y, So after every "y" term is differentiated it will be multiplied by dy/dx.

17) $y^3 +4 = 3x \\ 3y^2 \frac{dy}{dx} +0 = 3$
Then you solve for dy/dx as if its a variable.
$\frac{dy}{dx} = \frac{3}{3y^2} = \frac{1}{y^2}$

18) Here lets review product rule:
$(fg)' = f'g + fg'$
Take derivative of each term
$2x^2 = -3y^3 +3x^2y^3 \\ 4x = -9y^2 \frac{dy}{dx} + (6x)(y^3) + (3x^2)(3y^2 \frac{dy}{dx}) \\ 4x = -9y^2 \frac{dy}{dx} +6xy^3 +9x^2y^2 \frac{dy}{dx}$
Solve for dy/dx using factoring:
$4x - 6xy^3 = -9y^2 \frac{dy}{dx}+9x^2 y^2 \frac{dy}{dx} \\ 4x - 6xy^3 = \frac{dy}{dx}(-9y^2 +9x^2 y^2) \\ \frac{dy}{dx} = \frac{4x - 6xy^3}{-9y^2 +9x^2 y^2}$

8 0

3 years ago

Simplify: sec(θ) sin(θ) cot(θ)

krek1111 [17]

We have to simplify

sec(θ) sin(θ) cot(θ)

Now first of all let's simplify these separately , using reciprocal identities.

Sec(θ) = 1/cos(θ)

Sin(θ) is already simplified

Cot(θ)= cos(θ) / sin(θ) ,

Let's plug these values in the expression

sec(θ) sin(θ) cot(θ)

= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )

= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

sin cancels out with sin and cos cancels out with cos

So , answer comes out to be

=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )

= 1

4 0

3 years ago

Read 2 more answers

What scale factor was applied to the first rectangle to get the resulting image? The answer is a decimal. The big rectangle is 2

Juli2301 [7.4K]

Scale factor is always (new/original)

so it depends which rectangle came first. if it started as large and was dilated to the smaller one, then the ratio is (.5/2.5) which simplifies to 1/5 or 0.2.

3 0

3 years ago

Anyone know how to do this

svlad2 [7]

Answer:

The area of the rectangle on the left side is

$9cm \: \times 4cm = 36 {cm}^{2}$

The area of the bottom rectangle is

$6cm \times 2cm = 12 {cm}^{2}$

The total area of the composite figure will be

$36 {cm}^{2} + 12 {cm}^{2} = 48 {cm}^{2}$

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0

3 years ago