Answer:
C
Step-by-step explanation:
6(2m+5n)
12m+30n
Jacob had multiplied 6 to 2m right which is 12m but multiplied 6 and 5n wrong as he thought it was 11n yet it is 30n.
Answer:
(4, 5)
Step-by-step explanation:
Calculate the midpoint using the midpoint formula
midpoint = [( + ), ( + ) ]
with (, ) = (1, 2) and (, ) = (7, 8)
midpoint = [(1 + 7), (2 + 8) ]
= (4, 5)
9514 1404 393
Answer:
(x +6)^2 +(y -10)^2 = 225
Step-by-step explanation:
The standard form equation for a circle is ...
(x -h)^2 + (y -k)^2 = r^2
where the center is (h, k) and the radius is r.
The center of a circle is the midpoint of any diameter. The midpoint between two points is the average of their coordinates.
((-15, -2) +(3, 22))/2 = (-15+3, -2+22)/2 = (-6, 10)
The radius can be found using the distance formula, or by simply putting one of the given points in the equation for the circle to see what the constant (r^2) needs to be.
(x -(-6))^2 +(y -10)^2 = (-15-(-6))^2 +(-2-10)^2
(x +6)^2 +(y -10)^2 = 81 +144 = 225
The equation of the circle is ...
(x +6)^2 +(y -10)^2 = 225
Answer:
The quotient of two integers may not always be an integer.
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
Step-by-step explanation:
The student is not largely correct!
The sum, difference, and product of two integers is indeed always an integer.
But, the quotient of two integers may not always be an integer.
- For example, the quotient of integers 4 and 2 will be an integer.
i.e.
4/2 = 2
- But, if we take the quotient of 2 and 3, the result will not be an integer.
i.e.
2/3 = 0.67
Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.
Answer:
c. Korey will see an overall profit in his third year of business
Step-by-step explanation:
His cost for first year
= 12500+8000
=$ 20500
Profit first year= $12000
Net Profit first year= -$8500
Second year cost= $8000
Profit second year
= 12000+12000(0.06)
= 12000+720
=$ 12720
Net profit second year = -8500+12720-8000
= -3780
Third year
Cost = $8000
Profit= 12720+12720(0.06)
Profit=$13483.2
Net profit= 13483.2-8000-3780
Net profit= $1703.2
