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pishuonlain [190]
3 years ago
11

Please help!!!! The points are A(4,1) B(4,0) C(5,0)

Mathematics
2 answers:
devlian [24]3 years ago
6 0
A (0,1) B(0,0) C(1,0). It says subtract the x coordinate by 4, so that’s what you do.
Tema [17]3 years ago
6 0

Answer:

A. (0,1)

B. (0,0) Origin

C. (1,0)

Step-by-step explanation: Given points A(4,1) B(4,0) and C(5,0), we are told to find the coordinates of A, B and C when (x, y)-->(x-4, y). A(4,1) becomes A(4-4,1) which is A(0,1). B(4,0) becomes B(4-4,0) which is (0,0), and is also known as the origin of the graph. C(5,0) becomes C(5-4,0) which is (1,0). Hope that this makes sense. Have a great day!

Point A:

A(4,1)

A(4-4,1)

A(0,1)

Point B:

B(4,0)

B(4-4,0)

B(0,0)

Point C:

C(5,0)

C(5-4,0)

C(1,0)

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<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

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<h2>Step-by-step explanation:</h2>

In the question,

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We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

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<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

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<u>At, </u>

<u>n = 3</u>

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Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

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<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

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