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3 years ago

Use the drop-down menus to choose steps in order to correctly solve 6n+9=−3n−21−6 for n.

Mathematics

1 answer:

fomenos3 years ago

6 0

Answer:

n = - 4

Step-by-step explanation:

6n + 9 = -3n - 21 - 6

6n + 3n = - 21 - 6 - 9

9n = - 27 - 9

9n = -36

n = -36/9

n = - 4

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4(3x+5)= -4

NeX [460]

Answer/explanation

4(3x+5)=-4

You will distribute the four to every term in the parenthesis,

12x+20=-4

Then you will combine like terms

12x+20=-4

-20 -20

12x=-24

Then you will divide 12 to isolate x

$\frac{12x}{-24} =\frac{-24}{-24}$

Obviously, -24 cancels out and you would get x=-2

4 0

4 years ago

Written as a simplified polynomial in standard form, what is the result when

ANEK [815]

Answer:

- 2x² + 3x + 64

Step-by-step explanation:

3x - (2x-8)² Write the equation and distribute the exponent

3x - 2x² + 64 Write the equation in order of degree of exponents, or standard form

- 2x² + 3x + 64

6 0

4 years ago

Find ∂w/∂s and ∂w/∂t using the appropriate Chain Rule.

Vesnalui [34]

Answer:

<h3>The value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3><h3>The value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

Step-by-step explanation:

Given that the Function point are $w=y^3-9x^2y$

$x=e^s$ , $y=e^t$ and s = -5, t = 10

<h3>To find $\frac{\partial w}{\partial s}$ and $\frac{\partial w}{\partial t}$ using the appropriate Chain Rule : </h3>

$w=y^3-9x^2y$

Substitute the values of x and y in the above equation we get

$w=(e^t)^3-9(e^s)^2(e^t)$

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to s by using chain rule we have </h3>

$\frac{\partial w}{\partial ∂s}=e^{3t}-9(e^{2s}).2(e^t)$

$=e^{3t}-18e^{2s}.(e^t)$

$=e^{3t}-18e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3>

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to t by using chain rule we have </h3>

$\frac{\partial w}{\partial t}=e^{3t}.(3)-9e^{2s}(e^t).(1)$

$=3e^{3t}-9e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3>

Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :

$\frac{\partial w}{\partial s}=e^{3t}-18e^{2s+t}$

$=e^{3(10}-18e^{2(-5)+10}$

$=e^{30}-18e^{-10+10}$

$=e^{30}-18e^0$

$=e^{30}-18$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3>

$\frac{\partial w}{\partial t}=3e^{3t}-9e^{2s+t}$

$=3e^{3(10)}-9e^{2(-5)+10}$

$=3e^{30}-9e{-10+10}$

$=3e^{30}-9e{0}$

$=3e^{30}-9$

$\frac{\partial w}{\partial t}=3(e^{30}-3)$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

6 0

3 years ago

a store owner has 63.5 pounds of candy if splits the candy into 5 boxes how many pounds of candy will be each box contain

NemiM [27]

This is a division problem.
Divide 63.5 by 5.

12.7
----------------------------
5 | 63.5
- 5
-------
13
- 10
------
35
- 35
--------
0

Answer: 12.7 lb

4 0

4 years ago

Read 2 more answers

Which list of numbers are all prime numbers? 2, 3, 9, 25 2, 3, 5, 11 2, 3, 5, 11 2, 3, 7, 9 2, 3, 7, 9 3, 5, 11, 15 2, 3, 9, 25

BARSIC [14]

Answer:25 2, 11 2,15 2

Step-by-step explanation:

5 0

3 years ago