Which of the decimals or fractions is not equal to 0.825 or ?

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

I believe it would be option A 0.85, I do know C & D do equal so either A or B would be the answer of not equaling

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Least to greatest -2.14, 1 3/4, -1 1/8, -2.19

sergey [27]

Answer:

-1.375, -2.19, -2.14, 3.25

6 0

3 years ago

Joe is learning to play the trumpet. on Monday he practiced from 6:30 until 7:05.on Tuesday he practiced from 3:55 until 4:15. h

valina [46]

Let's start with day 1:

We know that Joe practiced from 6:30 to 7:05
An hour is 60 minutes
Joe practiced for the 30 minutes left in that hour and 5 minutes into the next

30+5=35

So, he was playing for 35 minutes on the first day

Now, we can do the same thing for the second day:

He started at 3:55 and ended at 4:15
An hour is 60 minutes
<span>Joe practiced for the 5 minutes left in the hour and the first 15 minutes of the next hour
</span>
5+15=20

Now we want to add the number of minutes he practiced for both days

35+20=55 minutes

6 0

3 years ago

Read 2 more answers

1Y, the number of accidents per year at a given intersection, is assumed to have a Poisson distribution. Over the past few years

miss Akunina [59]

Answer:

The probability that the intersection will come under the emergency program is 0.1587.

Step-by-step explanation:

Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.

Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.

For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.

Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

$W = \frac{X-\mu}{\sigma} = \frac{X-3}{1/2} = 2x-6$

The values of $\phi$ , the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program