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Make 2 equations one for the price and one for quantity. so first set x = AA and y= AAA. for price 37= 1x+.75y. now for the quantity we have x+y=42. Now we can solve by subtracting the equation for price from the equation for quantity and we get .25y =5. solving this we get y= 20. Now we plug that value back in and solve for x. 22 double A's and 20 triple A's.
Cost per mile P- total cost (C) divided by total miles (M).
P= C/M
The probability that one of each color is selected is 
<h3>Probabilities</h3>
The probability of an event is the chances of the said event
The given parameters are:
- Total = 10
- Red = x
- Blue = 10 - x
<h3>Calculating the required probability</h3>
The probability that one of each color is selected is calculated as follows:
So, we have:
This gives
Take LCM
Simplify the above expression
Expand
Hence, the probability that one of each color is selected is
Read more about probabilities at:
brainly.com/question/7965468
Answer:
0.01364
Step-by-step explanation:
It is given that,
A store sells a 33-pound bag of oranges for $3.60 and a 55-pound bag of oranges for $5.25.
Price per pound of 33 pound bag is 3.60/33 = 0.10909 price per pound
Price per pound of 55 pound bag of oranges is 5.25/55 = 0.09545 price per pound
Difference between price per pound for the 33-pound bag of oranges and the price per pound for the 55-pound bag of oranges is :
D = 0.10909 - 0.09545
D = 0.01364
Therefore, this is the required solution.
