Answer:
81.8%
Step-by-step explanation:
Mean = ![\mu = 40](https://tex.z-dn.net/?f=%5Cmu%20%3D%2040)
Standard deviation = ![\sigma = 5](https://tex.z-dn.net/?f=%5Csigma%20%3D%205)
Now we are supposed to find out what percent of the numbers fall between 35 and 50
![z = \frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Substitute the values
![z = \frac{x-40}{5}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7Bx-40%7D%7B5%7D)
Now for P(35<x<50)
Substitute x = 35
![z = \frac{35-40}{5}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B35-40%7D%7B5%7D)
![z =-1](https://tex.z-dn.net/?f=z%20%3D-1)
Substitute x = 50
![z = \frac{50-40}{5}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B50-40%7D%7B5%7D)
![z =2](https://tex.z-dn.net/?f=z%20%3D2)
So, P(-1<z<2)
P(z<2)-P(z<-1)
=0.9772-0.1587
=0.8185
= ![0.818 \times 100](https://tex.z-dn.net/?f=0.818%20%5Ctimes%20100)
=81.8%
Hence 81.8% percent of the numbers fall between 35 and 50
What you need to do is subtract since the key word "How much Less money" is in it.
$9.956-$50 = 40.044$
I assume the first equation is supposed to be
![5x-3y+2z=13](https://tex.z-dn.net/?f=5x-3y%2B2z%3D13)
and not
![5x-3x+2x=4x=13](https://tex.z-dn.net/?f=5x-3x%2B2x%3D4x%3D13)
As an augmented matrix, this system is given by
![\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D5%26-3%262%2613%5C%5C2%26-1%26-3%261%5C%5C4%26-2%264%2612%5Cend%7Barray%7D%5Cright%5D)
Multiply through row 3 by 1/2:
![\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D5%26-3%262%2613%5C%5C2%26-1%26-3%261%5C%5C2%26-1%262%266%5Cend%7Barray%7D%5Cright%5D)
Add -1(row 2) to row 3:
![\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D5%26-3%262%2613%5C%5C2%26-1%26-3%261%5C%5C0%260%265%265%5Cend%7Barray%7D%5Cright%5D)
Multiply through row 3 by 1/5:
![\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D5%26-3%262%2613%5C%5C2%26-1%26-3%261%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Add -2(row 3) to row 1, and add 3(row 3) to row 2:
![\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D5%26-3%260%2611%5C%5C2%26-1%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Add -3(row 2) to row 1:
![\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D-1%260%260%26-1%5C%5C2%26-1%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Multiply through row 1 by -1:
![\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%261%5C%5C2%26-1%260%264%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Add -2(row 1) to row 2:
![\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%261%5C%5C0%26-1%260%262%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Multipy through row 2 by -1:
![\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%260%260%261%5C%5C0%261%260%26-2%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
The solution to the system is then
![\boxed{x=1,y=-2,z=1}](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D1%2Cy%3D-2%2Cz%3D1%7D)
Answer:
Answer in explanation
Step-by-step explanation:
Before this we do this question let's get fimiliar with what's a function.
A function is a equation that when graphed, each input(x) correspond to one output(y). This means one inputs can't map to the diffrent output.
The vertical line test is just puting a vertical line anywhere on the function. If the vertical line touches more than two points your graph is not a function. If it touches one you graph is a function. The reason is because a vertical line that touches 2 points means one x maps to two diffrent y and thats not a function.
In conclusion the graph does pass the vertical line test so it is a function.
Hope this helped!,
JoeLouis2
Answer:
c
Step-by-step explanation:
10 times 8 = 80
80 times 3 = 240