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3 years ago

Help please and thank you

Mathematics

1 answer:

Otrada [13]3 years ago

3 0

Answer:

For the first one im pretty sure its 81

For the second one, Im pretty sure its 30.

sorry if theyre wrong... :(

Step-by-step explanation:

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. A. 139 B. 147° C. 155 D. 157 PLEASE HELP ASAAAPP!

enyata [817]

Answer:

$\huge\boxed{157 \ \ \text{degrees}}$

Step-by-step explanation:

In order to find the value of ∠EFB here, we have to note our angle relationships.

We know that ∠CFE is already 90°. We also know that ∠CFA is 90°. Angle ∠AFB is inside ∠CFA. Since we know the measure of ∠AFB, we can find the measure of ∠BFC.

$23 + x = 90\\\\x = 90-23\\\\x = 67$

Now that we know ∠CFE and ∠BFC, which together make ∠BFE, we can add these angles up.

$90+67=157$

Hope this helped!

5 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

Before making invitations, Katrina counted the supplies she bought for her party.

aleksandrvk [35]

The GCF of 36 and 81 is 9

36/9 = 4 water balloons
81/9 = 9 beads

Katrina can invite 9 friends, with each getting 4 water balloons and 9 beads

5 0

3 years ago

Read 2 more answers

1/secA-tanA - 1 /secA+tanA So the answer comes 2tanA/sec^2 A-tan^2A how ??.

solniwko [45]

Answer:

Hope it helps

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7 0

3 years ago

Choose a linear function for the line represented by the point-slope equation y – 5 = 3(x – 2).

babunello [35]

Step-by-step explanation:

This an answer see in picture

4 0

3 years ago