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3 years ago

I need help please :(((;

Mathematics

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

yes because of the lines they are the same on both triangles

Step-by-step explanation:

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Find the area of the circle below???

olga55 [171]

Answer:

Area of the circle = $24.618\,feet^2$

Step-by-step explanation:

Radius of the circle= $2.8\,feet$

Area of the circle= $\pi \times r^2$

As,

$\pi =\dfrac{22}{7} =3.14$

Area of the circle is:

$=3.14\times 2.8 \times 2.8\\\\= 3.14 \times 7.84\\\\=24.618\,feet^2$

The Area of the circle is : $24.618\,feet^2$

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B25%7D%20%2B%5Csqrt%7B9%7D%20%3D%20%3F" id="TexFormula1" title="\sqrt{25} +\sqrt{9} =

inn [45]

Answer:

$\boxed{8}$

Step-by-step explanation:

$Simplify \: the \: following : \\ = > \sqrt{25} + \sqrt{9} \\ \\\sqrt{25} = \sqrt{ {5}^{2} } = 5: \\ = > 5 + \sqrt{9} \\ \\ \sqrt{9} = \sqrt{ {3}^{2} } = 3: \\ 5 + 3 \\ \\ 5+3=8: \\ Answer:8$

3 0

3 years ago

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What percent of 3 upon 5 is 1 upon 25?

vfiekz [6]

Answer:

3/5/100*1/25

=3/20*1/25

=3/500

3 0

3 years ago

Find the y-intercept and the x-intercept of the line 2x-4y=10

kompoz [17]

Finding y intercept and x intercept is easy:

X intercept will be of the form (x,0) and y intercept will be of the form (0,y)

● If you put x=0 in the equation, you will get y-intercept.

● If you put y=0 in the equation, you will get x-intercept.
______________________________

Given equation: 2x - 4y = 10

◆ Put x = 0
2×0 - 4y = 10
=> -4y = 10
=> y = 10/(-4)
=> y = -5/2

Thus y intercept is (0, -5/2)

◆Put y = 0
2x - 4×0 = 10
=> 2x = 10
=> x = 10/2
=> x = 5

Thus the x intercept is (5,0)

4 0

3 years ago

What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir

I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0

3 years ago