Answer: The probability that the two children have the disease is 1/16 or 6,25%
Explanation: If the disease only occurs in homozygous individuals and the parents have the trait but not the disease that means is a recesive allele and the parents are heterozygous for this trait.
According to proportions stablished by Mendel, when there is a cross between 2 heterozygous (Ss x Ss) indivdials the probability to obtain a homozygous recesive (ss) descendant is 25% or 1/4 as shown in punnet square below:
Taking into account that the condition of the first kid does not imply the condition for the second, it should be analyzed as 2 independent events.
1. First kid has 1/4 of probability have the dissease as shown in punnet square
2. For a second birth, child has the 25% chance to have the disease
The probability that both events to happen is the product of each event probabilty:
p = 1/4 * 1/4 = 1/16 or 6,25%
Answer:
Add all of the numbers, then divide by the number off addends
Explanation:
Example:
20, 45, 93. 45
1. Add all of the numbers.
203
2. Divide by the number of addends (4)
50.75
The average is 50.75
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The nucleus, water in them, organelles.
Hoped this helped.
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Answer:
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Explanation:
Have a great day. :)
The Scyphozoa Class (phylum Cnidaria) consists of marine organisms known as true jellyfishes. The characteristics of true jellyfish include four horseshoe-shaped gonads located in the umbrella.
The term Scyphozoa indicates the like-cup shape of the jellyfish. Moreover, the term 'true jellyfish' is used to recognize different species of the Scyphozoa class.
The most conspicuous phenotypic trait of a true jellyfish is its umbrella-shaped bell.
The true jellyfishes are translucent organisms characterized by four (4) gonads which can be observed at the top of the bell. This species also has four stomach pouches described as gastric pockets.
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