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kolbaska11 [484]
3 years ago
11

The sum of three consecutive multiples of 3 is equal to 6 more than four times the smallest multiple. What is the largest multip

le ?.
a.)9
b.)12
c.)15
d.)18
Mathematics
2 answers:
Setler79 [48]3 years ago
5 0

Answer:  (a) 9

<u>Step-by-step explanation:</u>

1st multiple of 3: 1(3x)

2nd multiple of 3: 2(3x)

3rd multiple of 3: 3(3x)

Sum = 4(1st multiple of 3) + 6


1(3x) + 2(3x) + 3(3x) = 4(3x) + 6

 3x  +    6x  +    9x  =  12x  + 6

                        18x  = 12x + 6

                          6x =           6

                            x = 1


Largest (3rd) multiple is: 3(3x)

                                      = 9x

                                      = 9 · 1

                                      = 9

kvv77 [185]3 years ago
3 0
Answer for this one is a
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Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

8 0
3 years ago
The average household income for a recent year was $30,000. five years earlier the average household income was $24,500. assume
ikadub [295]

Using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

According to the question,

The average household income for a recent year (x₁⁻) = $30,000

The average household income for a recent year (x₂⁻) = $24,500

sample sizes n₁ = n₂ = 34

standard deviation of both samples were $24,500. Thus, s₁ = s₂ = $5928.

Null hypothesis:  There is no evidence to believe that the average household income has increased.

H₀ : μ₁ ≤ μ₂

Alternative hypothesis:  There is evidence to believe that the average household income has increased.

H₁: μ₁ > μ₂  

To check hypothesis we have the formula

Standard error=  \sqrt{\frac{s_{1} ^{2} }{n_{1} } + \frac{s^{2} _{2} }{n_{2} }  }

= \sqrt{2067128.4706}

= 1437.7512

Thus, standard error is $1437.7512.

Formula for test statistic = [(x₁⁻ -  x₂⁻) - (μ₁ - μ₂)]/standard error

= [(30000 -  24500) - 0]/1437.7512

= 3.8254

The critical value of z at 5% level of significance is 1.6449.

Here, the calculated value is greater than the critical value so we reject H₀.

Hence using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

Learn more about hypothesis test here

brainly.com/question/15060525

#SPJ2

3 0
2 years ago
B/5&gt;-1<br> Solve the inequality. Graph and check the solution.
Usimov [2.4K]

Answer:

b>-5

Step-by-step explanation:

\frac{b}{5}   >  - 1

Multiply by 5 to isolate b.

b  >  - 5

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.

If you put any number greater than -5, you'll output greater than - 1.

4 0
3 years ago
What is the inverse property of the complex number 9-4i
Zina [86]

Answer:

when added to the original number, would equate to zero. Another term this may be known as is the additive identity. The additive inverse is simply:

(a + bi) = -(a + bi)

Given: 9 - 4i

-(9 - 4i) = -9 + 4i

Therefore, the answer is B.

6 0
3 years ago
www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb
damaskus [11]

Answer:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

Step-by-step explanation:

For this problem we have the following parameters given:

\mu = 40, \sigma =8

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

z=\frac{X-\mu}{\sigma}

And replacing we got:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

5 0
3 years ago
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