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Lelechka [254]
3 years ago
7

295 + 39x = 350 - 33x solve for x and show work

Mathematics
2 answers:
Katarina [22]3 years ago
7 0

Answer:

x=\frac{55}{72}

Step-by-step explanation:

295+39x=350-33x

Subtract 295 from both sides:

39x=-33x+55

Add 33x to both sides:

72x=55

Divide both sides by 72:

x=\frac{55}{72}

Misha Larkins [42]3 years ago
6 0
Question
295+39x=350-33x

Answer
295+39x=350-33x
295+39x+33x=350
39x+33x=350-295
72x=350-295
72x=55
X= 55/72
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Lindsay says all numbers that are multiples of 4 have 2 as a factor. Is lindsay correct?
m_a_m_a [10]

Answer:

Yes

Step-by-step explanation:

Let's take any random multiple of 4 as an example:

8 = 2 • 4

64 = 2 • 32

20 = 2 • 10

Try any multiple of 4—this pattern continues.

7 0
3 years ago
A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.
arlik [135]
Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound

mixture:
twice as many peanuts as almond; total cost of mixture is 21.

a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a

1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3

almonds = 3 lbs
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raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs

<span>My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins </span>
8 0
3 years ago
Read 2 more answers
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
Which of the following relationships is a direct variation?
mafiozo [28]

Answer:Well All i know is that the answer is not C I'm sorry I dont know the correct answer but I know for a fact that the answer isn't C

Step-by-step explanation:

4 0
3 years ago
Can someone please help me answer this question
Allushta [10]

Answer:

720

Step-by-step explanation:

60 minutes in a hour. So add 30 for each 20 minutes so it would be 90 an hour so multiply 90 by 8

7 0
2 years ago
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