First, arrange the numbers in order.
50, 55, 58, 60, 62, 64, 68, 70, 72, 76, 84, 92
the minimum (or lower-extreme) would be 50, since it is the lowest number.
the lower quartile would be 59, since 58 and 60 are the two middle numbers on the lower side, you would do 58+60 / 2.
the median would be 66, since 64 and 68 are the two middle numbers. you would do 64+68 / 2.
the upper quartile would be 74, since 72 and 76 are the two middle numbers on the upper side, you would do 72+76 / 2.
the maximum (or upper-extreme) would be 92 since it is the largest number.
to graph, put in your numbers at the bottom (i would probably count by twos). then plot your minimum, lower quartile, median, upper quartile, and maximum. next, draw a box around the lower quartile and upper quartile with the median inside the box. lastly, extend two lines from the left and right side of the box connecting to the minimum and maximum.
i hope this makes sense ! this is what goes through my head when i solve these kinds of problems lol
Answer:
B ≥ 209
Step-by-step explanation:
This is the equation - 25b + 525 ≥ 5750 .
Comment if I solved it incorrectly ;-;
Answer:
Step-by-step explanation:
Given the mass is m =16kg, and 1N force will stretch the spring 1 m.
That is, F =1N,Z =1m. Now find the spring constant k:
F = kL = 1 = k(1) = k= 1N/m.
The damping force is 8times the instantaneous velocity, this means β = 8,
and the external force is f(t) = 0
Initially the object compressed 0.6m above equilibrium position,
with the downward velocity is 2m/s.
The differential equation for a spring mass system with
damping force and extemal force is: mx" + βxt + kx = f(t).
so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.
Now solve the DE:
The auxilary equation for the homogeneous equation is 16x"+8x'+x=0
solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.
Then the general solution for the homogenous system is: 
.
Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:
.
Hence, 
.
Q + r + s.....q = 46, s = 54
46 + r + 54
100 + r <==
P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555
