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il63 [147K]
3 years ago
7

Write 6.3 x 10^4 in standard notation.

Mathematics
2 answers:
icang [17]3 years ago
6 0
The power of 4 means to move the decimal 4 places to the right. 6.3 x 10^4
63000
kompoz [17]3 years ago
3 0
63000 you move the decimal point 4 places to the right
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1 -sin^2x÷csc^1x=sinx^2<br>​
Stella [2.4K]

Answer: 37

Step-by-step explanation:

6 0
2 years ago
Math help @LIEMONDER
klio [65]
First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)
5 0
3 years ago
What is the constant term for -2a3b2+5ab5+7b4+8
stiv31 [10]

Hey there!

<u>Constant terms</u> are the terms where no variables are there (only the constant, i.e, the number). So, here the term <em><u>8</u></em><em><u> </u></em><em><u> </u></em>is the constant term because it doesn't have any variables.

Hope it helps ya!

8 0
3 years ago
In the numerical sentence below, A = 8, D = 1/2 , and F = 1/4. What are the values B, C, and E if the sentence below is equivale
a_sh-v [17]
B=3; C=16; and E=4096.

Using the information we have gives us

8^B \times C^{\frac{1}{2}} = E^{\frac{1}{4}}

We know that:
8^B = 2;&#10;\\&#10;\\C^{\frac{1}{2}}=4;&#10;\\&#10;\\E^{\frac{1}{4}}=8

We know that 2³ = 8, so B = 3.

To "undo" a square root, we square the number; 4²=16, so C = 16.

To "undo" a fourth root, we raise the answer to the fourth power; 8⁴ = 4096, so E = 4096.
3 0
3 years ago
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Answer: 1. True 2. True 3. False. Number 4 True

Step-by-step explanation: PLS GIVE ME BRAINIEST

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