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Galina-37 [17]
4 years ago
11

Michael is packing his bags for his vacation. He has 6 unique books, but only 4 fit in his bag. How many different groups of 4 b

ooks can he take?
Mathematics
1 answer:
goldfiish [28.3K]4 years ago
3 0

Answer:

15

Step-by-step explanation:

Michael has 6 unique books, but 4 not-unique slots. Since the slot is not unique, the orders you pick the 4 books are not important. When order important you use permutation but since the order is not important you use the combination. The calculation will be:

6C4 = \frac{6!}{6!(6-4)!} = 15

There are 15 ways to group the 4 books.

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Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each
julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}

a)

P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2) . And

P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0
3 years ago
Tiffany wants to illustrate the homework times she and some of her friends spent one night on one subject. Her goal is to show t
chubhunter [2.5K]
My best guess is a line graph because it shows the consistent numbers and then you can lay them all out after you have completed the graph
8 0
4 years ago
Read 2 more answers
Jill borrows a pencil and returns it after the Warm Up. She then borrows a different pencil to show work on her CFA.  The proba
mestny [16]

Probabilities are used to determine the chances of events

The probability that Jill selects a wooden pencil and then a mechanical pencil is 8%

<h3>How to calculate the probability</h3>

Represent the events as follows:

  • A represents mechanical pencil
  • B represents wooden pencil
  • C represents colored pencil

So, we have

P(A) = 20%

P(B) = 40%

P(C) = 30%

The probability that Jill selects a wooden pencil and then a mechanical pencil is then calculated as:

P(B n A) = P(B) * P(A)

This gives

P(B n A) = 40% * 20%

Evaluate the product

P(B n A) = 8%

Hence, the probability that Jill selects a wooden pencil and then a mechanical pencil is 8%

Read more about probabilities at:

brainly.com/question/9385303

4 0
3 years ago
Help please due in 10 min
vlada-n [284]

Answer:

I think it's 20 I think I'm not sure but try to solve it

5 0
3 years ago
43. Can you place ten lumps of sugar in three empty cups so that
erma4kov [3.2K]

Answer: No.

Step-by-step explanation:

We have 10 lumps of sugar, and we want to divide them into 3 cups, in such a way that there is an odd number of lumps in each cup.

This only can happen if we have 3 odd numbers such that the addition is equal to 10.

Now 10 is an even number, remember that even numbers can be written as:

2*k

where k is an integer number.

And odd numbers can be written as:

2*n + 1

where n is an integer.

Then we have 3 odd numbers, let's call them:

(2*n + 1), (2*k + 1) and (2*p + 1).

Now let's add them:

(2*n + 1) + (2*k + 1) + (2*p + 1).

2*(n + k + p) + 1 + 1+ 1

2*(n + k + p) + 2 + 1 =

2*(n + k + p + 1) + 1.

Now, the number n + k + p + 1 is an integer number, let's call it X, then we have that the addition of the 3 odd numbers is:

2*X + 1

This is an odd number

So for any 3 odd numbers that we add together, the result will always be an odd number.

Then is impossible to add 3 odd numbers and get 10 as the result (Again, 10 is an even number).

Then is not possible to have an odd number of lumps in each cup.

5 0
3 years ago
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