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Kazeer [188]
3 years ago
10

Please answer question #2 and please show work

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

9514 1404 393

Answer:

  2a. (360x +495)/(8x +11) = 45

  2b. 2((8x+11) +45) = 16x +112

Step-by-step explanation:

a) The area is the product of length and width.

  A = LW

We are given ...

  W = 8x +11

  A = 360x +495

The value of length can be found by solving for L:

  L = A/W

  L = (360x +495)/(8x +11)

The long-division solution to this is shown in the attachment.

  L = 45 . . . . simplified expression for length

__

b) The perimeter of the tank is twice the sum of length and width:

  P = 2(L +W)

Substituting the values for L and W, this is ..

  P = 2(45 +(8x +11)) . . . . expression for length of edge seal

  P = 2(8x +56)

  P = 16x + 112 . . . . . . simplified expression for seal length

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