Please answer question #2 and please show work
1 answer:
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Answer:
2a. (360x +495)/(8x +11) = 45
2b. 2((8x+11) +45) = 16x +112
Step-by-step explanation:
a) The area is the product of length and width.
A = LW
We are given ...
W = 8x +11
A = 360x +495
The value of length can be found by solving for L:
L = A/W
L = (360x +495)/(8x +11)
The long-division solution to this is shown in the attachment.
L = 45 . . . . simplified expression for length
__
b) The perimeter of the tank is twice the sum of length and width:
P = 2(L +W)
Substituting the values for L and W, this is ..
P = 2(45 +(8x +11)) . . . . expression for length of edge seal
P = 2(8x +56)
P = 16x + 112 . . . . . . simplified expression for seal length
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Answer:
Step-by-step explanation:
The identities you need here are:
and
You also need to know that
x = rcosθ and
y = rsinθ
to get this done.
We have
r = 6 sin θ
Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):
r² = 6r sin θ
Now let's replace r² with what it's equal to:
x² + y² = 6r sin θ
Now let's replace r sin θ with what it's equal to:
x² + y² = 6y
That looks like the beginnings of a circle. Let's get everything on one side because I have a feeling we will be completing the square on this:
Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.
The y linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:
In the process of completing the square, we created within that set of parenthesis a perfect square binomial:
And there's your circle! Third choice down is the one you want.
Fun, huh?