$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-6}{2}~~,~~\cfrac{y+3}{2} \right)~~=~~\stackrel{\stackrel{Midpoint}{M}}{(-2~,~3)}\implies \begin{cases} \cfrac{x-6}{2}=-2\\[1em] x-6=-4\\ \boxed{x=2}\\ \cline{1-1} \cfrac{y+3}{2}=3\\[1em] y+3=6\\ \boxed{y=3} \end{cases}$

7 0

4 years ago

Can someone explain this to me or help me get the answer? it is about centroids in triangles.

nadezda [96]

Answer: A centroid of a triangle is the point where the three medians of the triangle meet that is what i got on my test hope this helps :)

7 0

4 years ago

Given that (8,-4) is on the graph of f(x), find the corresponding point for the function f(x+3)

Margarita [4]

Answer:

the corresponding point is (5,-4)

Step-by-step explanation:

x+3=8 <=> x =8-3=5

so f(5+3)=f(8)=-4

so the corresponding point is (5,-4)

6 0

3 years ago