Describe two ways you can use a table to write a proportion

1 answer:

4 0

Https://www.bigideasmath.com/protected/content/ipe/grade%207/03/g7_03_04.pdf. click on this link and here you go with the answer!!!!

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Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x

Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a) $\int\limits^3_0 {(10-x)-(x+4)} \, dx$ ( option D )

b) A = 1/2 (6)(3) ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area = $\int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy$ ( note a = 10 )

= y^2/2 - 4y |⁷₄ + 10y - y^2/2 |¹⁰₇

= 33/2 - 12 + 30 - 51/2 = 9

hence the best integral from the options attached is option D

$\int\limits^3_0 {(10-x)-(x+4)} \, dx$

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12 = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

= 1/2 * 6 * 3

= 9

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Teenage Mutant Ninja Turtles desmos

grigory [225]

Answer:

i agree

Step-by-step explanation:

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2 years ago

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How much should you put in an investment paying a simple interest rate of 5% if you needed $4000 in eighteen mont

Eddi Din [679]

now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P$