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Makovka662 [10]

3 years ago

7

The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant. A. The cost for 1 a

dult is $ . The cost for 1 child is $ .

1 answer:

Liono4ka [1.6K]3 years ago

4 0

Answer: The total cost is $\$62$ assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$

Step-by-step explanation:

Assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$ :

$a=\$5$ and $c=\$2$

Then the expression that gives the total cost $10 a+6c$ is solved as:

$10(\$5)+6(\$2)=\$62$

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lawyer [7]

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The function f(x)=70n -400 models the profit of the instructor of a guitar class per month, where n is the number of students en

suter [353]

Given:
f(x) = 70n - 400 : equation for monthly profit.
n = number of students enrolled in the guitar class.

70 refers to the amount charged per student.
400 is the fixed expense made by the instructor.

For the instructor to have a profit, the product of 70n must be more than 400.

400/70 = 5.7 or 6

There must be at least 6 students enrolled in class for the instructor to generate profit.

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3 0

3 years ago

7z2 5z4 d3 d8<br> I don't know how you are supposed to do it?

Serga [27]

Answer:

$35 {z}^{6} {d}^{11}$

Step-by-step explanation:

Assuming you are supposed to simplify:

$7 {z}^{2} \times 5 {z}^{4} \times {d}^{3} \times {d}^{8}$

Then we need to apply the product rule of indices.

${a}^{m} \times {a}^{n} = {a}^{m + n}$

So we multiply to get:

$35 {z}^{2 + 4} \times {d}^{3 + 8}$

We now simplify the exponents to get:

$35 {z}^{6} \times {d}^{11}$

Therefore the required product is

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3 years ago

Find the third side in simplest radical form:<br> 25

Gre4nikov [31]

Answer:

<h3> $\boxed{ \bold{24}}$ </h3>

Step-by-step explanation:

$\mathsf{given}$

$\mathsf{hypotenuse(h) = 25}$

$\sf{perpendicular (p) = 7}$

$\sf{base(b) = }$ ?

Now, Using Pythagoras theorem

$\sf{{h}^{2} = {p}^{2} + {b}^{2} }$

plug the values

⇒ $\sf{ {25}^{2} = {7}^{2} + {b}^{2} }$

Evaluate the power

⇒ $\sf{625 = 49 + {b}^{2} }$

Swap the sides of the equation

⇒ $\sf{49 + {b}^{2} = 625}$

Move constant to right hand side and change it's sign

⇒ $\sf{ {b}^{2} = 625 - 49}$

Calculate the difference

⇒ $\sf{ {b}^{2} = 576}$

Squaring on both sides

⇒ $\sf{b = 24}$

Hope I helped!

Best regards!

8 0

3 years ago