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leva [86]
3 years ago
13

I think this is the hardest question But if you solve this you will get 500+ points

Mathematics
2 answers:
elixir [45]3 years ago
8 0

Answer:

40

Step-by-step explanation:

Let the number of 20cent coins be 'x'

Then, 10cent coins are 'x + 12'

Total amount = $5.4 = 540 cents

20(x) + 10(x + 12) = 540

20x + 10x + 120 = 540

30x = 540 - 120

30x = 420

x = 420/30

x = 14 (14 20cent coins)

x + 12 = 26 (26 10cent coins)

Total coins = 14 + 26 = 40

BRAINLIST

Step-by-step explanation:

blondinia [14]3 years ago
6 0

Answer:

40

Step-by-step explanation:

Let the number of 20cent coins be 'x'

Then, 10cent coins are 'x + 12'

Total amount = $5.4 = 540 cents

20(x) + 10(x + 12) = 540

20x + 10x + 120 = 540

30x = 540 - 120

30x = 420

x = 420/30

x = 14 (14 20cent coins)

x + 12 = 26 (26 10cent coins)

Total coins = 14 + 26 = 40

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8

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(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.
DaniilM [7]

Answer:

The answer is "\frac{2}{9} \  and \ \frac{1}{9}"

Step-by-step explanation:

In point a:

The requires  1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They can pick 1 Chunin form of the matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They have the option to pick 1 join from of the country team with such a probability: \frac{1}{\binom{3}{1}}=\frac{1}{3}

And we can make the country teams: 3! = 6 different forms. Its chances of choosing a team full in the process described also are:

6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: \frac{1}{\binom{3}{1}}=\frac{1}{3}

Its odds of choosing the same rank ninja in such a different country team are: \frac{1}{\binom{3}{1}}=\frac{1}{3}

The likelihood of choosing the same level Ninja from the residual matter of national is: \frac{1}{\binom{3}{1}}=\frac{1}{3} Therefore, all 3 selected ninjas are likely the same grade: 3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}

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