Twelve less than a number, all divided by 18 as a numeric expression. Plzz I will give you 100 points

Brianna is solving a directed line segment question. Part of the problem reads: Y lies on segment XZ such that the ratio of XY t

goldenfox [79]

Answer:

⅕

Step-by-step explanation:

Given that points X, Y, and Z are collinear, and X is said to partition segment XZ in the ratio XY to XZ = 1:5, it means that segment XY = ⅕ of XZ. That is XY/XZ = ⅕

See attachment below to understand how point Y divides segment XZ.

Therefore, the k value Brianna would use when solving the problem should be the fraction, ⅕.

k value = XY/XZ = 1/5

8 0

3 years ago

3. Which expression is equivalent to log532?

8090 [49]

Step-by-step explanation:

The Nth power xN of the integer x was initially specified as x multiplied by itself, before the total number N is the same. By means of different generalizations, the concept may be generalized to any value of N that is any real number.

(2) The logarithm (to base 10) of any number x is defined as the power N such that

x = 10N

(3) Properties of logarithms:

(a) The logarithm of a product P.Q is the sum of the logarithms of the factors

log (PQ) = log P + log Q

(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors

log (P / Q) = log P – log Q

(c) The logarithm of a number P raised to power Q is Q.logP

log[PQ] = Q.logP

6 0

3 years ago

Y=3x-7y=3x−7 Complete the missing value in the solution to the equation. (1,_) PLEASE QUICK

kkurt [141]

Answer:

-4

Step-by-step explanation:

The two equations you have are:

y = 3x - 7

x = 1 (this comes from the x value being 1)

To solve for y, use the substitution property of equality to replace x in the equation:

where x = 1,

y = 3(1) - 7

y = -4

8 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −

Korolek [52]

The vector field

$\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k$

has curl

$\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath$

Parameterize $S$ by

$\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k$

where

$\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}$

with $0\le u\le3$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k$

Then by Stokes' theorem we have

$\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv$

which has a value of 0, since each component integral is 0:

$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

4 0

3 years ago

Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])

maxonik [38]

Step-by-step explanation:

Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])

Given

first term a1 = -2

second term a2 = 2

We are to get the first 8 terms. Given the sequence

a[n]=a[n-2](3-a[n-1])

a[3]=a[3-2](3-a[3-1])

a[3]=a[1](3-a[2])

a[3]=-2(3-2)

a3 = -2

a[n]=a[n-2](3-a[n-1])

a[4]=a[4-2](3-a[4-1])

a[4]=a[2](3-a[3])

a[4]=2(3+2)

a4= 10

a[5]=a[n-2](3-a[n-1])

a[5]=a[5-2](3-a[5-1])

a[5]=a[3](3-a[4])

a[5]=-3(3-10)

a5 = -3(-7)

a5 = 21

a[6]=a[n-2](3-a[n-1])

a[6]=a[6-2](3-a[6-1])

a[6]=a[4](3-a[5])

a[6]= 10(3-21)

a6 = 10(-18)

a6 = -180

a[n]=a[n-2](3-a[n-1])

a[7]=a[7-2](3-a[7-1])

a[7]=a[5](3-a[6])

a[7]= 21(3+180)

a7 = 21(183)

a7 = 3,843

a[8]=a[n-2](3-a[n-1])

a[8]=a[8-2](3-a[8-1])

a[8]=a[6](3-a[7])

a[8]=-180(3-3843)

a8 = -180(-3840)

a8 = 691,200

6 0

3 years ago