Answer:
⅕
Step-by-step explanation:
Given that points X, Y, and Z are collinear, and X is said to partition segment XZ in the ratio XY to XZ = 1:5, it means that segment XY = ⅕ of XZ. That is XY/XZ = ⅕
See attachment below to understand how point Y divides segment XZ.
Therefore, the k value Brianna would use when solving the problem should be the fraction, ⅕.
k value = XY/XZ = 1/5
Step-by-step explanation:
The Nth power xN of the integer x was initially specified as x multiplied by itself, before the total number N is the same. By means of different generalizations, the concept may be generalized to any value of N that is any real number.
(2) The logarithm (to base 10) of any number x is defined as the power N such that
x = 10N
(3) Properties of logarithms:
(a) The logarithm of a product P.Q is the sum of the logarithms of the factors
log (PQ) = log P + log Q
(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors
log (P / Q) = log P – log Q
(c) The logarithm of a number P raised to power Q is Q.logP
log[PQ] = Q.logP
Answer:
-4
Step-by-step explanation:
The two equations you have are:
y = 3x - 7
x = 1 (this comes from the x value being 1)
To solve for y, use the substitution property of equality to replace x in the equation:
where x = 1,
y = 3(1) - 7
y = -4
The vector field

has curl

Parameterize
by

where

with
and
.
Take the normal vector to
to be

Then by Stokes' theorem we have



which has a value of 0, since each component integral is 0:




Step-by-step explanation:
Give the first 8 terms of the sequence. a1= -1, a2=2, a[n]=a[n-2](3-a[n-1])
Given
first term a1 = -2
second term a2 = 2
We are to get the first 8 terms. Given the sequence
a[n]=a[n-2](3-a[n-1])
a[3]=a[3-2](3-a[3-1])
a[3]=a[1](3-a[2])
a[3]=-2(3-2)
a3 = -2
a[n]=a[n-2](3-a[n-1])
a[4]=a[4-2](3-a[4-1])
a[4]=a[2](3-a[3])
a[4]=2(3+2)
a4= 10
a[5]=a[n-2](3-a[n-1])
a[5]=a[5-2](3-a[5-1])
a[5]=a[3](3-a[4])
a[5]=-3(3-10)
a5 = -3(-7)
a5 = 21
a[6]=a[n-2](3-a[n-1])
a[6]=a[6-2](3-a[6-1])
a[6]=a[4](3-a[5])
a[6]= 10(3-21)
a6 = 10(-18)
a6 = -180
a[n]=a[n-2](3-a[n-1])
a[7]=a[7-2](3-a[7-1])
a[7]=a[5](3-a[6])
a[7]= 21(3+180)
a7 = 21(183)
a7 = 3,843
a[8]=a[n-2](3-a[n-1])
a[8]=a[8-2](3-a[8-1])
a[8]=a[6](3-a[7])
a[8]=-180(3-3843)
a8 = -180(-3840)
a8 = 691,200