This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
The digit 2 would be in the hundred thousands place because if you say it out loud its "three million, two hundred fifty four thousand, one hundred and seven"
58 because 80 times 15 percent is 12. so you subtract 12 from 80 that gives you 68 then you subtract the coupon which is 10 dollars. you total is 58.
Find the vertex: -4x^2 + 16x - 7
Vertex = ( x, f(x)).
x = -b/2a
x = -16/2(-4)
x = -16/-8
x = 2
f(x) = -4x^2 + 16x - 7
Let x = 2
f(2) = -4(2)^2 + 16(2) - 7
f(2) = -4(4) + 32 - 7
f(2) = -16 + 32 - 7
f(2) = 16 - 7
f(2) = 9
Vertex = (2, 9)
