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GenaCL600 [577]
3 years ago
6

mr. j graded papers for 6.7 hours mr. bellanger graded papers for 12 hours. for how many more hours did mr. bellanger grade than

mr. j
Mathematics
1 answer:
Elza [17]3 years ago
3 0
5hours and 30 minutes more
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Los divisores de 100 son tambien divisores de 50 ?
sergiy2304 [10]

Answer:

La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}

Step-by-step explanation:

8 0
2 years ago
Helpppppppppppppo anyone
Alenkasestr [34]

Answer: 50653

37³ = (40 - 3)³ = 40³ - 3.40².3 + 3.40.3² - 3³

= 64000 - 14400 + 1080 - 27

= 50653

Step-by-step explanation:

3 0
2 years ago
Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e
aleksandr82 [10.1K]

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y  0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

7 0
3 years ago
What is the slope of the line that<br> passes through these two points?<br> (-1, 4)<br> (2, 2)
Dimas [21]

Answer:

-2/3x

Step-by-step explanation:

1.) use the slope equation (y2-y1)/(x2-x1)

2.) substitute the points into the equation (2-4)/(2--1)

3.) solve the equation (2-4= -2) / (2--1=3)

4.) the slope is -2/3

5 0
3 years ago
What is the vertex of x^2 -10x + 21
Radda [10]

Answer:

(5, - 4)

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

x² - 10x + 21 ← is in standard form

with a = 1, b = - 10, so

x_{vertex} = - \frac{-10}{2} = 5

Substitute x = 5 into the quadratic for the corresponding value of y

y = 5² - 10(5) + 21 = 25 - 50 + 21 = - 4

vertex = (5, - 4)

5 0
3 years ago
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