It must be less than 90 because acute triangles have angle under 90
Answer:
r=0.5 or 1/2
Step-by-step explanation:
if you multiply 0.5 to each Xs you can find out why r is 0.5
Answer:
B i believe
Step-by-step explanation:
Answer:
the prices were $0.05 and $1.05
Step-by-step explanation:
Let 'a' and 'b' represent the costs of the two sodas. The given relations are ...
a + b = 1.10 . . . . the total cost of the sodas was $1.10
a - b = 1.00 . . . . one soda costs $1.00 more than the other one
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Adding these two equations, we get ...
2a = 2.10
a = 1.05 . . . . . divide by 2
1.05 -b = 1.00 . . . . . substitute for a in the second equation
1.05 -1.00 = b = 0.05 . . . add b-1 to both sides
The prices of the two sodas were $0.05 and $1.05.
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<em>Additional comment</em>
This is a "sum and difference" problem, in which you are given the sum and the difference of two values. As we have seen here, <em>the larger value is half the sum of the sum and difference</em>: a = (1+1.10)/2 = 1.05. If we were to subtract one equation from the other, we would find <em>the smaller value is half the difference of the sum and difference</em>: b = (1.05 -1.00)/2 = 0.05.
This result is the general solution to sum and difference problems.
Answer:
Domain= {
}
Step-by-step explanation:
The function given is: 
, and we are asked to find the Domain of it. Let's recall that the Domain of a function is the set of all x-values for which the function is defined (can be evaluated rendering a real number as result). So in order to find which x-values constitute such Domain, let's investigate for which x-values we can effectively evaluate the square root of "x+6".
Notice that the square root is not defined for radicands that are negative (less than zero). The only radicands that are allowed are those greater than or equal to zero. So that is exactly the condition we want to impose on the radicand: to be greater than or equal to zero (
). Our radicand is the expression: "x+6", so we write in math terms the necessary condition as:
and solve for "x" in the inequality (isolating "x" on one side:
The Domain of this function is therefore all those real "x" values that are greater than or equal to negative 6 ()
