All categories

3 years ago

Please help me with this math question I really need help ;/. I'll give brainliest if u help.

Mathematics

1 answer:

Darya [45]3 years ago

7 0

Step-by-step explanation: You have to substitute the numbers in for x & y

(0, -5): YES

3x - 4y - 8 = 12

3(0) - 4(-5) - 8 = 12

0 + 20 - 8 = 12

20 - 8 = 12

12 = 12

(4, -2): YES

3x - 4y - 8 = 12

3(4) - 4(-2) - 8 = 12

12 + 8 - 8 = 12

20 - 8 = 12

12 = 12

(8, 2): NO

3x - 4y - 8 = 12

3(8) - 4(2) = 12

24 - 8 = 12

16 = 12

(-16, -17): YES

3x - 4y - 8 = 12

3(-16) - 4(-17) - 8 = 12

-48 + 68 - 8 = 12

20 - 8 = 12

12 = 12

(-1, -8): NO

3x - 4y - 8 = 12

3(-1) - 4(-8) = 12

-3 + 32 = 12

29 = 12

(-40, -34): NO

3x - 4y - 8 = 12

3(-40) - 4(-34) - 8 = 12

-120 + 136 - 8 = 12

16 - 8 = 12

8 = 12

Hope this help you!!! :)

You might be interested in

It says 7/6x= 140 I am lost can somebody please help me

kobusy [5.1K]

7/6x=140

since variable x is multiplied by 7/6, find x by multiplying by the inverse of 7/6 which is 6/7.

7/6x × 6/7 = 140 × 6/7
x= 120

8 0

3 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)

Read more about rhombus at:

brainly.com/question/20627264

#SPJ1

8 0

2 years ago

Which symbol makes the statement true? <br> |15| ? -12<br> <<br> ><br> =<br> ≥

swat32

Answer:

Step-by-step explanation:

Absolute value means whatever is inside of it is always positive so 15 is greater than -12.

3 0

3 years ago

Need a quick answer pls

Lubov Fominskaja [6]

Answer:

(3,3)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Math (10 points) please help

Eddi Din [679]

Answer:

x = - 1, y = 4

Step-by-step explanation:

A. We are going to use elimination method because we have +2y and -2y, and when we add these equations +2y and -2y are going to be eliminated.

x + 2y = 7

4x = - 4

x = - 1

x + 2y = 7

-1 + 2y = 7

2y = 8

y = 4

3 0

3 years ago