The given function is greater than or equal to 0 for the interval given as follows:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
<h3>When a function is positive and when it is negative?</h3>
- A function is positive when it is above the x-axis.
- A function is negative when it is below the x-axis.
For this problem, with a closed interval, we have that the function is above for:
x ≤ -3, -1 ≤ x ≤ 0, x ≥ 2.
Hence the interval notation is:
{x | x ≤ -3 or -1 ≤ x ≤ 0 or x ≥ 2}.
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The measures of the angles are given to be x and y. Since y is 65 degrees less than the measure of angle x then, it can also be expressed as x - 65. The sum of the angles x and y should be 180 degrees as they are supplementary angles,
x + y = 180
x + (x - 65) = 180
The value of x is 122.5 and that of y is 57.5. Therefore, the measures of the angles are 122.5 and 57.5.
Answer:
3 is 60°, as well as 5 and 7 and the rest are 120°
Step-by-step explanation:
Answer:
Could You Please Explain More?
Step-by-step explanation:
Answer:a
Step-by-step explanation:
h(x)=x-12
h(x)=4x-48
h(x)=-1(4x-48)
h(x)=-4x+48
h(x)=48-4x