From the information given, the cost function is given as C=125q + 13500 while the value of q is given as 270. Therefore, on order to find the cost, we'll slot in the value of q into the equation given. This will be:

C=125q + 13500

C = 125(270) + 13500

C = 33750 + 13500

C = 47250

In conclusion, the cost is 47250.

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6 0

3 years ago

Consider the displacement field: u1 = k(2X 2 1 + X1X2), u2 = kX2 2 , u3 = 0, k = 10−4 (2) (a) Find the elongation per unit lengt

ZanzabumX [31]

Answer:

I suggest asking your proffesor

Step-by-step explanation:

sorry I couldn't help you this time

4 0

3 years ago

Find the length of BC. <br> A.) 14<br> B.) 9<br> C.) 2<br> D.) 3

Vera_Pavlovna [14]

Answer:

A) 14

Step-by-step explanation:

BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.

3y+5=5y-1

subtract 3y from both sides --> 5=2y-1

add 1 to both sides --> 6=2y

now get y alone, divide by 2 by both side --> y=3

plug y in back to 5y-1 --> 5x3-1

15-1

BC = 14

7 0

3 years ago

At the beginning of a population study, a city had 390,000 people. Each year since, the population has grown by 7.3% . Let t be

Xelga [282]

T=number of years since start of the study.
y=city´s population.

first year:
y=390,000+0.073(390,000)=390,000(1+0.073) (=418470)

Second year:
y=(390,000(1+0.073) + 0.073(390,000(1+0.073) =
=390,000(1+0.073) (1+0.073)
=390,000(1+0.073)²
(≈449,018.31)

Third year: if you calculate it you would have:
y=390,000(1+0.073)³

Fourth year: if you compute it you would have:
y=390,000 (1+0.073)⁴

t th year:
y=390,000(1+0.073)^t

Answer: y=390,000(1+0.073)^t

6 0

3 years ago