Answer:
The reasonable range for the population mean is (61%, 75%).
Step-by-step explanation:
The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.
The mean of the sampling distribution of sample proportion is,
.
One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

Given:
n = 150
= 0.68
The critical value of <em>z</em> for 95% confidence level is:

Compute the 95% confidence interval for proportion as follows:


Thus, the reasonable range for the population mean is (61%, 75%).
Answer:
x = 13 smaller integer
x + 2 = 15 the other integer
Step-by-step explanation:
x = the smaller integer
x + 2 = the next integer
7(x) = 61 + 2(x + 2)
7x = 61 + 2x +4
5x = 61 + 4
5x = 65
x = 13 smaller integer
x + 2 = 15 the other integer
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
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Ratio and portion
taggednow to tagged later comparison
assuming the tagged onws aer in ratio
25-16=9
9/25=0.36=36%
I would assume that the eagle population dropped 36%