!NEED HELP URGENTLY! p − 10p + -5p + 14p − -9p − 2 = -20

What is the slope of the line that passes through (3, −7) and (−1, 1)? (1 point)

ELEN [110]

Answer:

The slope of the line is -2

Step-by-step explanation:

The rule of the slope of a line is:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line

Let us find the slope using the rule above

∵ The line passes through points (3, -7) and (-1 , 1)

∴ $x_{1}$ = 3 and $x_{2}$ = -1

∴ $y_{1}$ = -7 and $y_{2}$ = 1

Substitute these values in the rule above to find m

∴ $m=\frac{1--7}{-1-3}=\frac{1+7}{-4}=\frac{8}{-4}=-2$

∴ The slope of the line that passes through the given points is -2

8 0

4 years ago

The ordered pair (0,4) is a soultion of which system

Anettt [7]

This question is asking you to substitute 0 for X and 5 for y in both equations. If the right hand value is equal to the left hand value after making the substitution, the answer is "yes". Otherwise, the answer is "no".
Substitute 0 for x and 5 for y in the first equation and then the second equation. Since 0 + 5 = 5 and -5*0 + 2*5 = 10 the answer

5 0

3 years ago

T.J. Had a car loan for $5800. Over the course of the loan, he paid a total of $1508 in interest at a rate of 6.5%. Over how man

kodGreya [7K]

Answer: it took T.J. 48 months to pay the car loan.

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P = principal or amount loaned

R = interest rate

T = time in years.

I = interest

From the information given,

P = $5800

R = 6.5%

Over the course of the loan, he paid a total of $1508 in interest. Therefore,

I = $1508 Therefore,

1508 = (5800×6.5×T)/100

1508 = 377T

T = 1508/377 = 4 years

Assuming there are 12 months in a year, the number of months in 4 years would be 4×12 = 48 months

5 0

4 years ago

If it takes 33

vivado [14]

Answer:

3.3 LBS

Step-by-step explanation:

33 pounds for 10 cups

33/10

3.3

7 0

3 years ago

A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual

lawyer [7]

Answer:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

7 0

4 years ago