In a cooking contest, the mean score for taste was 20, with a standard deviation of 2.8. One of the contestants received a score
of 14. Convert this score to a z score and tell if it is “usual” or “unusual.”
2 answers:
The answer is -2.14; unusual
Z score = n - mu / d where mu = mean and d = std dev.
for n = 14 we hav ez score of (14-20) / 2.8 = -2.143
unusual as he is in the bottom 5%
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